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-15x^2+5x+7=0
a = -15; b = 5; c = +7;
Δ = b2-4ac
Δ = 52-4·(-15)·7
Δ = 445
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{445}}{2*-15}=\frac{-5-\sqrt{445}}{-30} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{445}}{2*-15}=\frac{-5+\sqrt{445}}{-30} $
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